The game of fish, shrimp and crab is very simple:

　　The dealer turns three dice (six faces, namely fish, shrimp, crab, gourd, money, and ingot) and the player needs to press one of them. When the face of the dice is the one pressed by the player, the player can win the pressed money, but if two dice appear, it can win twice as much as three, and if not, it will lose the bet money.

　　Suppose all six figures are pressed by one block.

　　When all three dice are different, you don't lose money or make money.

　　When two of the three dice are the same, lose one

　　When three dice are the same, lose two pieces.

　　Why is this? We can solve it through mathematical expectation.

　　Suppose you press one, it is 3× 1/6× 5/6× 5/6× 2+3× 1/6× 1/6× 5/6× 3+1/6× 1/6× 4 = 199/216.

　　The first two 3s are C13 and C23 (it's not easy to fight here).

　　2 and the last 3 and 4 represent principal plus income.

　　Then the dealer is in a favorable position in playing fish, shrimp and crab.